- paul-uk a écrit:
- hello there is a big debate on an English site as to weather normal birds can carry the mutation cobalt a breeder claims to have bred a cobalt from 2 normal birds !
Bonjour, il y a un gros débat en Angleterre sur le fait que des oiseaux soient porteur de cobalt. Un éleveur a obtenu un cobalt hors d deux classiques !
i do not believe this is possible.
Je ne crois pas que c'est possible.
which couplings give you the darkest birds ?
Quel accouplement donne les oiseaux les plus foncés ?
also what would the results from these couplings be
Duel seraient les résultats de ces accouplements:
cobalt x brown => cobalt X brun
cobalt x browncobalt => cobalt X brun cobalt
browncobalt x brown => brun cobalt X brun
Hi.
Question 1:We don't name this genetic transfer "Cobalt" because that is not a recessive sex linked factor as for the canaries. At the redpols, that is a co-dominant factor similar to the diluted factor for the siskin. We name this factor "dark factor".
So, at redpols, you can have "single dark factor" or "double dark factor".
As we assume to call D the "dark factor" gene, the genetic formulas will be :
D+ for the unmodified wild gene
D+
D+ for the single modified gene as "single factor"
D
D for the double modified gene as "double factor"
D
So, according to the herebelow couplings, you can have :
1- Single dark factor X classic (wild) or opposite gives :50% classic birds (males or females)
50% single dark factor (males or females)
2- Single dark factor X single dark factor gives : 25% classic birds (males or females)
50% single dark factor (males or females)
25% double dark factor (males or females)
3- Single dark factor X double dark factor or opposite gives : 50% single dark factor (males or females)
50% double dark factor (males or females)
4- Double dark factor X classic (wild) or opposite gives :100% single dark factor (males or females)
5- Double dark factor X double dark factor gives : 100% double dark factor (males or females)
6- Double dark factor X single dark factor or opposite gives : refer to herabove point n° 3
So, it looks that is not possible to have dark factor form two classic redpols.
Question 2 :For myself, I think the darkest birds will be given by the classic birds.
Question 3:1a- classic single dark factor X brown gives :25% classic males split brown
25% classic males single dark factor split brown
25% classic females
25% classic females single dark factor
1b- classic double dark factor X brown gives :50% classic males single dark factor split brown
50% classic females single dark factor
2a- classic single dark factor X brown single dark factor gives :12.5% classic males split brown
25% classic males single dark factor split brown
12,5% classic males double dark factor split brown
12.5% classic females
25% classic females single dark factor
12,5% classic females double dark factor
2b- classic double dark factor X brown single dark factor or classic single dark factor X brown double dark factor gives :25% classic males single dark factor split brown
25% classic males double dark factor split brown
25% classic females single dark factor
25% classic females double dark factor
2c- classic double dark factor X brown double dark factor gives :50% classic males double dark factor split brown
50% classic females double dark factor
3a- brown single dark factor X brown gives :25% brown males
25% brown males single dark factor
25% brown females
25% brown females single dark factor
3b- brown double dark factor X brown gives :50% brown males single dark factor (males or females)
50% brown females single dark factor (males or females)
Sorry for poor english.
Best regards.
RC